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- ...mount amongst each tier of item; say you have 5 rares, 5 uncommons, and 10 commons (the actual distribution does not matter). take the 10%, divide by 5, and t ...d a 90% chance, the rares need 5 tickets each (because there's 2), and the commons need 9 tickets each. ...10 KB (1,664 words) - 15:28, 1 April 2023
- ...mount amongst each tier of item; say you have 5 rares, 5 uncommons, and 10 commons (the actual distribution does not matter). take the 10%, divide by 5, and t ...d a 90% chance, the rares need 5 tickets each (because there's 2), and the commons need 9 tickets each. ...13 KB (2,131 words) - 15:03, 25 February 2023
- // License: Creative Commons Attribution-ShareAlike 4.0 International ...6 KB (575 words) - 13:54, 15 July 2018
- // Creative Commons Attribution 4.0 International https://creativecommons.org/licenses/by/4.0/ ...29 KB (3,473 words) - 12:28, 27 February 2017